Arithmetic: Designed for Academies and SchoolsA.S. Barnes, 1841 - 340 pages |
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Page 41
... bushels of wheat worth 125 dollars , a cow worth 25 dollars , a colt worth 40 dollars , and pays the rest in cash : what amount of money does he Ans . 390 dollars . pay ? MULTIPLICATION OF SIMPLE NUMBERS . 21. If Charles gives 2 cents ...
... bushels of wheat worth 125 dollars , a cow worth 25 dollars , a colt worth 40 dollars , and pays the rest in cash : what amount of money does he Ans . 390 dollars . pay ? MULTIPLICATION OF SIMPLE NUMBERS . 21. If Charles gives 2 cents ...
Page 69
... bushels of wheat at 1 dollar per bushel , and takes in part payment a horse worth 65 dollars , a waggon worth 40 dollars , and the rest in cash . How much money did he receive ?, Ans . 23 dollars . 5. A farmer has 14 calves worth 4 ...
... bushels of wheat at 1 dollar per bushel , and takes in part payment a horse worth 65 dollars , a waggon worth 40 dollars , and the rest in cash . How much money did he receive ?, Ans . 23 dollars . 5. A farmer has 14 calves worth 4 ...
Page 83
... bushels of wheat come to at $ 1,25 bushel ? per Ans . $ 375 . 3. What will 85 pounds of tea come to at 1 dollar 371⁄2 cents per pound ? In this example we first consider that of a cent is equal to 5 mills . Then as $ 1,37 5 contains ...
... bushels of wheat come to at $ 1,25 bushel ? per Ans . $ 375 . 3. What will 85 pounds of tea come to at 1 dollar 371⁄2 cents per pound ? In this example we first consider that of a cent is equal to 5 mills . Then as $ 1,37 5 contains ...
Page 86
... pair of fowls at 37 cents a pair ; and three hams at $ 1,50 each : how ' much does he owe him ? Ans . $ 23,16 . 6. A farmer agrees to furnish a merchant 40 bushels 86 OF FEDERAL MONEY . Applications in the Four Rules, 86-88.
... pair of fowls at 37 cents a pair ; and three hams at $ 1,50 each : how ' much does he owe him ? Ans . $ 23,16 . 6. A farmer agrees to furnish a merchant 40 bushels 86 OF FEDERAL MONEY . Applications in the Four Rules, 86-88.
Page 87
... bushels of rye at 62 cents per bushel , and to take his pay in coffee at 16 cents a pound : how much coffee will he ... bushels of wheat , for which he receives $ 1,37 per bushel ; 500 bushels of potatoes at 29 cents a bushel ; 1000 ...
... bushels of rye at 62 cents per bushel , and to take his pay in coffee at 16 cents a pound : how much coffee will he ... bushels of wheat , for which he receives $ 1,37 per bushel ; 500 bushels of potatoes at 29 cents a bushel ; 1000 ...
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Common terms and phrases
4th term acres annex apples barrels Bought bushels bushels of wheat called cent per annum ciphers cloth cost common denominator composite number compound fraction contains cube root cubic Currency decimal fraction decimal places denominate number diameter different denominations dimes dividend division dollars drams Dry measure equal EXAMPLES expressed farthings Federal Money figures following RULE foot four gallon given number gives greater greatest common divisor Hence higher denomination hogshead hundred hundredths improper fractions inches interest least common multiple lower denomination lowest terms measure merchant miles millionths mills mixed number months multiplicand multiply number of terms numerator and denominator OPERATION ounces payment pence pints proper fraction quarts quotient Reduce remainder Repeat the Table shillings simple numbers square root subtract sugar tens tenths thousandths Troy weight tuns units VULGAR FRACTIONS weight whole number wine yards cost yards of cloth
Popular passages
Page 174 - Hence, for the division of decimals we have the following RULE. Divide as in simple numbers, and point off in the quotient, from the right hand, so many places for decimals as the decimal places in the dividend exceed those in the divisor; and if there are not so many, supply the deficiency ly prefixing ciphers.
Page 106 - 69. The denominations of time are years, months, weeks, days, hours, minutes, and seconds. 60 seconds sec. make 1 minute, marked m. 60 minutes - - - - 1 hour, - - - - hr. 24 hours 1 day, - - - - da. 7 days 1 week,
Page 175 - 13O. NOTE 1. When any decimal number is to be divided by 10, 100, 1000, &c. the division is made by removing the decimal point as many places to the left as there are O's in the divisor ; and if there be not so many figures on the left of the decimal point, the deficiency must be supplied by prefixing ciphers.
Page 255 - CASE I. § 185. To extract the cube root of a whole number. RULE. I. Point off the given number into periods of three figures each, by placing a dot over the place of units, a second over the place of thousands, and so on to the left : the left hand period will often contain less than
Page 107 - year. Thirty days hath September, April, June, and November; All the rest have thirty-one, Excepting February, twenty-eight alone. Q. What are the denominations of Time? How long
Page 106 - MEASURE. § 68. Dry measure is used in measuring all dry articles, such as grain, fruits, roots, salt, coal, &c. Its denominations are chaldrons, bushels, pecks, quarts, and pints. TABLE. 2 pints pt. make 1 quart, marked qt. 8 quarts - 1 peck, - pk. 4 pecks - 1 bushel, - bu. 36 bushels - 1 chaldron, - ch. ch. bu. pk. qt. pt. 1=36
Page 89 - 4 farthings marked far. make 1 penny marked d. 12 pence 1 shilling - s. 20 shillings - - - 1 pound - £. 21 shillings - - - 1 guinea £ sd far. 1 = 20 = 240 = 960 1 = 12 = 48 1 = 4 NOTE.—Farthings are generally expressed in fractions of a penny. Thus, for 1 farthing we write
Page 249 - III. Double the root already found and place it on the left for a divisor. Seek how many times the divisor is contained in the dividend, exclusive of the right hand figure, and place the figure in the root and also at the right of the divisor.
Page 249 - V. Double the whole root already found, for a new divisor, and continue the operation as before, until all the periods are brought down. Q. What is required when we wish to extract the square root of a number ? What is the greatest square of a single figure
Page 136 - dividing the greater by the less, then dividing the divisor by the remainder, and continuing to divide the last divisor by the last remainder until nothing remains. The last divisor will be the greatest common divisor sought. Q. Will the common divisor of two numbers divide their