Arithmetic: Designed for Academies and SchoolsA.S. Barnes, 1841 - 340 pages |
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Page 34
... paid in part 267 dollars , and afterwards paid the remainder 325 dollars : How much did he borrow ? Ans . 592 dollars . 5. At the Custom House , on the first day of June , there were entered 1800 yards of linen ; on the 10th , 2500 ...
... paid in part 267 dollars , and afterwards paid the remainder 325 dollars : How much did he borrow ? Ans . 592 dollars . 5. At the Custom House , on the first day of June , there were entered 1800 yards of linen ; on the 10th , 2500 ...
Page 39
... 1830 ? Ans . 45 years . 3. Suppose I lend a man 1565 dollars , and he dies , wing me 450 dollars : how much had he paid me ? Ans . 1115 dollars . 4. In five bags are different sums of money to SUBTRACTION OF SIMPLE NUMBERS . 39.
... 1830 ? Ans . 45 years . 3. Suppose I lend a man 1565 dollars , and he dies , wing me 450 dollars : how much had he paid me ? Ans . 1115 dollars . 4. In five bags are different sums of money to SUBTRACTION OF SIMPLE NUMBERS . 39.
Page 41
... paid him 977 dollars . How much did he owe him ? Ans . 418 . 3. I have a fortune of 2543 dollars to divide among my four sons , James , John , Henry , and Charles . I give James 504 dollars , John 600 dollars , and Henry 725 : how much ...
... paid him 977 dollars . How much did he owe him ? Ans . 418 . 3. I have a fortune of 2543 dollars to divide among my four sons , James , John , Henry , and Charles . I give James 504 dollars , John 600 dollars , and Henry 725 : how much ...
Page 52
... paid ; such bills are usually called Bills of Parcels . BILLS OF PARCELS . James Johnson New - York , Oct. 1 , 1838 . Bought of W. Smith . 4 Chests of tea , of 45 pounds each , at 1 doll . a pound . 3 Firkins of butter at 17 dolls . per ...
... paid ; such bills are usually called Bills of Parcels . BILLS OF PARCELS . James Johnson New - York , Oct. 1 , 1838 . Bought of W. Smith . 4 Chests of tea , of 45 pounds each , at 1 doll . a pound . 3 Firkins of butter at 17 dolls . per ...
Page 70
... paid 18050 dollars . He sold 50 acres for 60 dollars an acre , and the remainder stood him in 50 dollars per acre : how much land did he purchase ? Ans . 351 acres . OF FRACTIONS . § 42. The unit 1 represents an entire thing ; as 1 ...
... paid 18050 dollars . He sold 50 acres for 60 dollars an acre , and the remainder stood him in 50 dollars per acre : how much land did he purchase ? Ans . 351 acres . OF FRACTIONS . § 42. The unit 1 represents an entire thing ; as 1 ...
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Common terms and phrases
4th term acres annex apples barrels Bought bushels bushels of wheat called cent per annum ciphers cloth cost common denominator composite number compound fraction contains cube root cubic Currency decimal fraction decimal places denominate number diameter different denominations dimes dividend division dollars drams Dry measure equal EXAMPLES expressed farthings Federal Money figures following RULE foot four gallon given number gives greater greatest common divisor Hence higher denomination hogshead hundred hundredths improper fractions inches interest least common multiple lower denomination lowest terms measure merchant miles millionths mills mixed number months multiplicand multiply number of terms numerator and denominator OPERATION ounces payment pence pints proper fraction quarts quotient Reduce remainder Repeat the Table shillings simple numbers square root subtract sugar tens tenths thousandths Troy weight tuns units VULGAR FRACTIONS weight whole number wine yards cost yards of cloth
Popular passages
Page 174 - Hence, for the division of decimals we have the following RULE. Divide as in simple numbers, and point off in the quotient, from the right hand, so many places for decimals as the decimal places in the dividend exceed those in the divisor; and if there are not so many, supply the deficiency ly prefixing ciphers.
Page 106 - 69. The denominations of time are years, months, weeks, days, hours, minutes, and seconds. 60 seconds sec. make 1 minute, marked m. 60 minutes - - - - 1 hour, - - - - hr. 24 hours 1 day, - - - - da. 7 days 1 week,
Page 175 - 13O. NOTE 1. When any decimal number is to be divided by 10, 100, 1000, &c. the division is made by removing the decimal point as many places to the left as there are O's in the divisor ; and if there be not so many figures on the left of the decimal point, the deficiency must be supplied by prefixing ciphers.
Page 255 - CASE I. § 185. To extract the cube root of a whole number. RULE. I. Point off the given number into periods of three figures each, by placing a dot over the place of units, a second over the place of thousands, and so on to the left : the left hand period will often contain less than
Page 107 - year. Thirty days hath September, April, June, and November; All the rest have thirty-one, Excepting February, twenty-eight alone. Q. What are the denominations of Time? How long
Page 106 - MEASURE. § 68. Dry measure is used in measuring all dry articles, such as grain, fruits, roots, salt, coal, &c. Its denominations are chaldrons, bushels, pecks, quarts, and pints. TABLE. 2 pints pt. make 1 quart, marked qt. 8 quarts - 1 peck, - pk. 4 pecks - 1 bushel, - bu. 36 bushels - 1 chaldron, - ch. ch. bu. pk. qt. pt. 1=36
Page 89 - 4 farthings marked far. make 1 penny marked d. 12 pence 1 shilling - s. 20 shillings - - - 1 pound - £. 21 shillings - - - 1 guinea £ sd far. 1 = 20 = 240 = 960 1 = 12 = 48 1 = 4 NOTE.—Farthings are generally expressed in fractions of a penny. Thus, for 1 farthing we write
Page 249 - III. Double the root already found and place it on the left for a divisor. Seek how many times the divisor is contained in the dividend, exclusive of the right hand figure, and place the figure in the root and also at the right of the divisor.
Page 249 - V. Double the whole root already found, for a new divisor, and continue the operation as before, until all the periods are brought down. Q. What is required when we wish to extract the square root of a number ? What is the greatest square of a single figure
Page 136 - dividing the greater by the less, then dividing the divisor by the remainder, and continuing to divide the last divisor by the last remainder until nothing remains. The last divisor will be the greatest common divisor sought. Q. Will the common divisor of two numbers divide their