Arithmetic: Designed for Academies and Schools,(with Answers.)A. S. Barnes and Company, 1844 - 338 pages |
From inside the book
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Page 206
... for one year , determines the rate of interest , or rate per cent . The term per cent , means by the hundred . In the example above the rate of interest is 6 per cent , or $ 6 for the hundred . Had $ 8 been paid for the use of the $ 100 ...
... for one year , determines the rate of interest , or rate per cent . The term per cent , means by the hundred . In the example above the rate of interest is 6 per cent , or $ 6 for the hundred . Had $ 8 been paid for the use of the $ 100 ...
Page 207
... for the use of the principal ? What is the amount ? What determines the rate of interest ? What is the meaning of per cent ? What is legal interest ? What is meant by per annum ? How much is the interest per annum in most of the states ...
... for the use of the principal ? What is the amount ? What determines the rate of interest ? What is the meaning of per cent ? What is legal interest ? What is meant by per annum ? How much is the interest per annum in most of the states ...
Page 208
... cent per annum ? We first multiply the given sum $ 327,45 by the rate of interest , 6 per cent , leaving two places for decimals or cents at the right hand . Then to divide by 100 we remove the decimal point two places to the left ...
... cent per annum ? We first multiply the given sum $ 327,45 by the rate of interest , 6 per cent , leaving two places for decimals or cents at the right hand . Then to divide by 100 we remove the decimal point two places to the left ...
Page 209
Designed for Academies and Schools,(with Answers.) Charles Davies. 7. What is the interest on $ 211,26 for one year at 41 per cent per annum ? We first find the interest at 4 per cent , and then the interest for per cent : the sum is the ...
Designed for Academies and Schools,(with Answers.) Charles Davies. 7. What is the interest on $ 211,26 for one year at 41 per cent per annum ? We first find the interest at 4 per cent , and then the interest for per cent : the sum is the ...
Page 210
... cent per annum ? We first multiply by 4 and then add half the multiplicand . OPERATION . $ 327,47 4 half the months . 130988 16373 14,7361 Ans . $ 14,73 + . 3. What is the interest on $ 8975 for ten months at 6 per cent per annum ? Ans ...
... cent per annum ? We first multiply by 4 and then add half the multiplicand . OPERATION . $ 327,47 4 half the months . 130988 16373 14,7361 Ans . $ 14,73 + . 3. What is the interest on $ 8975 for ten months at 6 per cent per annum ? Ans ...
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Other editions - View all
Arithmetic: Designed for Academies and Schools (With Answers) (Classic Reprint) Charles Davies No preview available - 2018 |
Arithmetic: Designed for Academies and Schools (With Answers) (Classic Reprint) Charles Davies No preview available - 2018 |
Arithmetic: Designed for Academies and Schools (Classic Reprint) Charles Davies No preview available - 2017 |
Common terms and phrases
acres amount annex apples arithmetical arithmetical progression Arithmetical Series barrels Bought bushels bushels of wheat called carats cent per annum ciphers common denominator common difference contains cords cube root cubic decimal fraction decimal places denominate number diameter divided dividend division dollars drams equal EXAMPLES express farthings Federal Money feet figures find the interest following RULE foot gallon given number gives greatest common divisor Hence hogshead hundred hundredths improper fractions inches last term least common multiple lower denomination lowest terms merchant miles mills minuend mixed number mixture months multiplicand multiply number of terms OPERATION ounces paid payment pence pints pounds present value quarts quotient receive Reduce remainder Repeat the Table sell shillings simple numbers sold solid square root subtract sugar tare tens thousandths Troy weight tuns units vulgar fraction weight whole number wine worth yards of cloth
Popular passages
Page 279 - THE CONDITION of the above obligation is such, that if the above bounden James Wilson, his heirs, executors, or administrators, shall well and truly pay or cause to be paid, unto the above named John Pickens, his executors, administrators, or assigns, the just and full sum of Here insert the condition.
Page 74 - TABLE. 10 Mills (m.) = 1 Cent . . ct. 10 Cents = 1 Dime . . d. 10 Dimes = 1 Dollar . $. 10 Dollars = 1 Eagle . E.
Page 139 - Divide the numerator by the denominator. The quotient will be the whole number, and the remainder, if...
Page 140 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Page 264 - To find the contents of a cylinder, Multiply the area of the base by the altitude : the product will be the contents.
Page 245 - Distinguish the given number into periods of two figures each, by putting a point over the place of units, another over the place of hundreds, and so on, which points show the number of figures the root will consist of.
Page 107 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Page 34 - January 31, February 28, March 31, April 30, May 31, June 30, July 31, August 31, September 30, October 31, November 30, December 31.
Page 109 - OF PARTICULARS. 12 things make 1 dozen. 12 dozen ----- 1 gross. 12 gross, or 144 dozen - 1 great gross. ALSO, 20 things make 1 score. 112 pounds ----- 1 quintal offish.
Page 142 - To reduce a whole number to an equivalent fraction, having a given denominator. RULE. Multiply the whole number by the given denominator, and place the product over the said denominator, and it will form the fraction required.