Arithmetic: Designed for Academies and Schools,(with Answers.)A. S. Barnes and Company, 1844 - 338 pages |
From inside the book
Results 1-5 of 23
Page 40
... worth 1200 dollars ; he leaves 504 to his daughter , and the remainder to his son : what was the son's portion ? Ans . dollars . 13. Suppose a gentleman has an income of 3090 dollars a year , and pays for taxes 150 dollars , and expends ...
... worth 1200 dollars ; he leaves 504 to his daughter , and the remainder to his son : what was the son's portion ? Ans . dollars . 13. Suppose a gentleman has an income of 3090 dollars a year , and pays for taxes 150 dollars , and expends ...
Page 41
... worth 125 dollars , a cow worth 25 dollars , a colt worth 40 dollars , and pays the rest in cash : what amount of money does he pay ? Ans . dollars . MULTIPLICATION OF SIMPLE NUMBERS . $ 21 . If Charles gives 2 cents apiece for two ...
... worth 125 dollars , a cow worth 25 dollars , a colt worth 40 dollars , and pays the rest in cash : what amount of money does he pay ? Ans . dollars . MULTIPLICATION OF SIMPLE NUMBERS . $ 21 . If Charles gives 2 cents apiece for two ...
Page 69
... worth 65 dollars , a wagon worth 40 dollars , and the rest in cash . How much money did he receive ? Ans . 23 dollars . 5. A farmer has 14 calves worth 4 dollars each , 40 sheep worth 3 dollars each ; he gives them all for a horse worth ...
... worth 65 dollars , a wagon worth 40 dollars , and the rest in cash . How much money did he receive ? Ans . 23 dollars . 5. A farmer has 14 calves worth 4 dollars each , 40 sheep worth 3 dollars each ; he gives them all for a horse worth ...
Page 87
... worth $ 1,871 a bushel , 300 bushels of oats worth 37 cents a bushel , 250 bushels of corn worth 80 cents a bushel , 65 tons of hay worth $ 18 a ton ; and the increase of the live stock , had been , 5 two years old worth $ 8 a piece , 8 ...
... worth $ 1,871 a bushel , 300 bushels of oats worth 37 cents a bushel , 250 bushels of corn worth 80 cents a bushel , 65 tons of hay worth $ 18 a ton ; and the increase of the live stock , had been , 5 two years old worth $ 8 a piece , 8 ...
Page 128
... worth £ 50 : how much remained due ? Ans . £ 12. A farmer has 6T . 8cwt . 2qr . 14lb . of hay to be re- moved in 6 equal loads : how much must be carried at each load ? Ans . 1T . 1cwt . 1qr . 21lb . 13. A person at his death left ...
... worth £ 50 : how much remained due ? Ans . £ 12. A farmer has 6T . 8cwt . 2qr . 14lb . of hay to be re- moved in 6 equal loads : how much must be carried at each load ? Ans . 1T . 1cwt . 1qr . 21lb . 13. A person at his death left ...
Contents
193 | |
203 | |
206 | |
217 | |
223 | |
230 | |
236 | |
242 | |
81 | |
82 | |
89 | |
95 | |
102 | |
108 | |
116 | |
123 | |
130 | |
137 | |
147 | |
155 | |
164 | |
170 | |
179 | |
186 | |
248 | |
253 | |
256 | |
260 | |
262 | |
274 | |
281 | |
289 | |
295 | |
302 | |
306 | |
312 | |
319 | |
325 | |
331 | |
338 | |
Other editions - View all
Arithmetic: Designed for Academies and Schools (With Answers) (Classic Reprint) Charles Davies No preview available - 2018 |
Arithmetic: Designed for Academies and Schools (With Answers) (Classic Reprint) Charles Davies No preview available - 2018 |
Arithmetic: Designed for Academies and Schools (Classic Reprint) Charles Davies No preview available - 2017 |
Common terms and phrases
acres amount annex apples arithmetical arithmetical progression Arithmetical Series barrels Bought bushels bushels of wheat called carats cent per annum ciphers common denominator common difference contains cords cube root cubic decimal fraction decimal places denominate number diameter divided dividend division dollars drams equal EXAMPLES express farthings Federal Money feet figures find the interest following RULE foot gallon given number gives greatest common divisor Hence hogshead hundred hundredths improper fractions inches last term least common multiple lower denomination lowest terms merchant miles mills minuend mixed number mixture months multiplicand multiply number of terms OPERATION ounces paid payment pence pints pounds present value quarts quotient receive Reduce remainder Repeat the Table sell shillings simple numbers sold solid square root subtract sugar tare tens thousandths Troy weight tuns units vulgar fraction weight whole number wine worth yards of cloth
Popular passages
Page 279 - THE CONDITION of the above obligation is such, that if the above bounden James Wilson, his heirs, executors, or administrators, shall well and truly pay or cause to be paid, unto the above named John Pickens, his executors, administrators, or assigns, the just and full sum of Here insert the condition.
Page 74 - TABLE. 10 Mills (m.) = 1 Cent . . ct. 10 Cents = 1 Dime . . d. 10 Dimes = 1 Dollar . $. 10 Dollars = 1 Eagle . E.
Page 139 - Divide the numerator by the denominator. The quotient will be the whole number, and the remainder, if...
Page 140 - To reduce a mixed number to an improper fraction, — RULE : Multiply the whole number by the denominator of the fraction, to the product add the numerator, and write the result over the denominator.
Page 264 - To find the contents of a cylinder, Multiply the area of the base by the altitude : the product will be the contents.
Page 245 - Distinguish the given number into periods of two figures each, by putting a point over the place of units, another over the place of hundreds, and so on, which points show the number of figures the root will consist of.
Page 107 - Thirty days hath September, April, June, and November ; All the rest have thirty-one, Except the second month alone, Which has but twenty-eight, in fine, Till leap year gives it twenty-nine.
Page 34 - January 31, February 28, March 31, April 30, May 31, June 30, July 31, August 31, September 30, October 31, November 30, December 31.
Page 109 - OF PARTICULARS. 12 things make 1 dozen. 12 dozen ----- 1 gross. 12 gross, or 144 dozen - 1 great gross. ALSO, 20 things make 1 score. 112 pounds ----- 1 quintal offish.
Page 142 - To reduce a whole number to an equivalent fraction, having a given denominator. RULE. Multiply the whole number by the given denominator, and place the product over the said denominator, and it will form the fraction required.